(1-2i)(2+3i)=

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Solution for (1-2i)(2+3i)= equation:


Simplifying
(1 + -2i)(2 + 3i) = 0

Multiply (1 + -2i) * (2 + 3i)
(1(2 + 3i) + -2i * (2 + 3i)) = 0
((2 * 1 + 3i * 1) + -2i * (2 + 3i)) = 0
((2 + 3i) + -2i * (2 + 3i)) = 0
(2 + 3i + (2 * -2i + 3i * -2i)) = 0
(2 + 3i + (-4i + -6i2)) = 0

Combine like terms: 3i + -4i = -1i
(2 + -1i + -6i2) = 0

Solving
2 + -1i + -6i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(1 + -2i)(2 + 3i) = 0

Subproblem 1

Set the factor '(1 + -2i)' equal to zero and attempt to solve: Simplifying 1 + -2i = 0 Solving 1 + -2i = 0 Move all terms containing i to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2i = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2i = 0 + -1 -2i = 0 + -1 Combine like terms: 0 + -1 = -1 -2i = -1 Divide each side by '-2'. i = 0.5 Simplifying i = 0.5

Subproblem 2

Set the factor '(2 + 3i)' equal to zero and attempt to solve: Simplifying 2 + 3i = 0 Solving 2 + 3i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 3i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 3i = 0 + -2 3i = 0 + -2 Combine like terms: 0 + -2 = -2 3i = -2 Divide each side by '3'. i = -0.6666666667 Simplifying i = -0.6666666667

Solution

i = {0.5, -0.6666666667}

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