(1-2y)(1+2y)=

Solution for (1-2y)(1+2y)= equation:

Simplifying
(1 + -2y)(1 + 2y) = 0

Multiply (1 + -2y) * (1 + 2y)
(1(1 + 2y) + -2y * (1 + 2y)) = 0
((1 * 1 + 2y * 1) + -2y * (1 + 2y)) = 0
((1 + 2y) + -2y * (1 + 2y)) = 0
(1 + 2y + (1 * -2y + 2y * -2y)) = 0
(1 + 2y + (-2y + -4y2)) = 0

Combine like terms: 2y + -2y = 0
(1 + 0 + -4y2) = 0
(1 + -4y2) = 0

Solving
1 + -4y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -4y2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4y2 = 0 + -1
-4y2 = 0 + -1

Combine like terms: 0 + -1 = -1
-4y2 = -1

Divide each side by '-4'.
y2 = 0.25

Simplifying
y2 = 0.25

Take the square root of each side:
y = {-0.5, 0.5}