(1-2y)/(3-y)=(1)(y+2)

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Solution for (1-2y)/(3-y)=(1)(y+2) equation: 


D( y )

3-y = 0

3-y = 0

3-y = 0

3-y = 0 // - 3

-y = -3 // * -1

y = 3

y in (-oo:3) U (3:+oo)

(1-(2*y))/(3-y) = 1*(y+2) // - 1*(y+2)

(1-(2*y))/(3-y)-(1*(y+2)) = 0

(1-2*y)/(3-y)-y-2 = 0

(1-2*y)/(3-y)+(-y*(3-y))/(3-y)+(-2*(3-y))/(3-y) = 0

1-y*(3-y)-2*(3-y)-2*y = 0

y^2-5*y+2*y-6+1 = 0

y^2-3*y-5 = 0

y^2-3*y-5 = 0

y^2-3*y-5 = 0

DELTA = (-3)^2-(-5*1*4)

DELTA = 29

DELTA > 0

y = (29^(1/2)+3)/(1*2) or y = (3-29^(1/2))/(1*2)

y = (29^(1/2)+3)/2 or y = (3-29^(1/2))/2

(y-((3-29^(1/2))/2))*(y-((29^(1/2)+3)/2)) = 0

((y-((3-29^(1/2))/2))*(y-((29^(1/2)+3)/2)))/(3-y) = 0

((y-((3-29^(1/2))/2))*(y-((29^(1/2)+3)/2)))/(3-y) = 0 // * 3-y

(y-((3-29^(1/2))/2))*(y-((29^(1/2)+3)/2)) = 0

( y-((29^(1/2)+3)/2) )

y-((29^(1/2)+3)/2) = 0 // + (29^(1/2)+3)/2

y = (29^(1/2)+3)/2

( y-((3-29^(1/2))/2) )

y-((3-29^(1/2))/2) = 0 // + (3-29^(1/2))/2

y = (3-29^(1/2))/2

y in { (29^(1/2)+3)/2, (3-29^(1/2))/2 }

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