(1-3i)/(4i-2)

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Solution for (1-3i)/(4i-2) equation:


D( i )

4*i-2 = 0

4*i-2 = 0

4*i-2 = 0

4*i-2 = 0 // + 2

4*i = 2 // : 4

i = 2/4

i = 1/2

i in (-oo:1/2) U (1/2:+oo)

(1-(3*i))/(4*i-2) = 0

(1-3*i)/(4*i-2) = 0

1-3*i = 0 // - 1

-3*i = -1 // : -3

i = -1/(-3)

i = 1/3

i = 1/3

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