(1-3x)/4=(x-2)/2

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Solution for (1-3x)/4=(x-2)/2 equation: 


x in (-oo:+oo)

(1-(3*x))/4 = (x-2)/2 // - (x-2)/2

(1-(3*x))/4-((x-2)/2) = 0

(1-3*x)/4-((x-2)/2) = 0

(1-3*x)/4+(-1*(x-2))/2 = 0

(2*(1-3*x))/(2*4)+(-1*4*(x-2))/(2*4) = 0

2*(1-3*x)-1*4*(x-2) = 0

10-10*x = 0

(10-10*x)/(2*4) = 0

(10-10*x)/(2*4) = 0 // * 2*4

10-10*x = 0

10-10*x = 0 // - 10

-10*x = -10 // : -10

x = -10/(-10)

x = 1

x = 1

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