(1-3x)/5=(x+3)/2

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Solution for (1-3x)/5=(x+3)/2 equation: 



(1-3x)/5=(x+3)/2

We move all terms to the left:

(1-3x)/5-((x+3)/2)=0

We add all the numbers together, and all the variables

(-3x+1)/5-((x+3)/2)=0

We calculate fractions


(-3x)/()+(-((x+3)*5)/()=0



We calculate terms in parentheses: +(-((x+3)*5)/(), so:

-((x+3)*5)/(

We multiply all the terms by the denominator


-((x+3)*5)



We calculate terms in parentheses: -((x+3)*5), so:

(x+3)*5

We multiply parentheses

5x+15

Back to the equation:

-(5x+15)



We get rid of parentheses

-5x-15

Back to the equation:

+(-5x-15)



We get rid of parentheses

(-3x)/()-5x-15=0

We multiply all the terms by the denominator


(-3x)-5x*()-15*()=0

We add all the numbers together, and all the variables

(-3x)-5x*()=0

We get rid of parentheses

-3x-5x*()=0

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