(1-3x)2=3(5+x)

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Solution for (1-3x)2=3(5+x) equation: 



(1-3x)2=3(5+x)

We move all terms to the left:

(1-3x)2-(3(5+x))=0

We add all the numbers together, and all the variables

(-3x+1)2-(3(x+5))=0

We multiply parentheses

-6x-(3(x+5))+2=0



We calculate terms in parentheses: -(3(x+5)), so:

3(x+5)

We multiply parentheses

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

-6x-3x-15+2=0

We add all the numbers together, and all the variables

-9x-13=0

We move all terms containing x to the left, all other terms to the right

-9x=13

x=13/-9

x=-1+4/9

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