(1-3y)(4-y)/(2-3y)(1-y)=1

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Solution for (1-3y)(4-y)/(2-3y)(1-y)=1 equation: 



(1-3y)(4-y)/(2-3y)(1-y)=1

We move all terms to the left:

(1-3y)(4-y)/(2-3y)(1-y)-(1)=0



Domain of the equation: (2-3y)(1-y)!=0

We move all terms containing y to the left, all other terms to the right

-3y)(1-y!=-2

y∈R



We add all the numbers together, and all the variables

(-3y+1)(-1y+4)/(-3y+2)(-1y+1)-1=0

We multiply parentheses ..

(+3y^2-12y-1y+4)/(-3y+2)(-1y+1)-1=0

We multiply all the terms by the denominator


(+3y^2-12y-1y+4)-1*(-3y+2)(-1y+1)=0

We get rid of parentheses

3y^2-12y-1y-1*(-3y+2)(-1y+1)+4=0

We multiply parentheses ..

3y^2-1*(+3y^2-3y-2y+2)-12y-1y+4=0

We add all the numbers together, and all the variables

3y^2-1*(+3y^2-3y-2y+2)-13y+4=0

We move all terms containing y to the left, all other terms to the right

3y^2-1*(+3y^2-3y-2y+2)-13y=-4

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