(1-9y)/5=(19+3y)/8

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Solution for (1-9y)/5=(19+3y)/8 equation: 



(1-9y)/5=(19+3y)/8

We move all terms to the left:

(1-9y)/5-((19+3y)/8)=0

We add all the numbers together, and all the variables

(-9y+1)/5-((3y+19)/8)=0

We calculate fractions


(-9y)/()+(-((3y+19)*5)/()=0



We calculate terms in parentheses: +(-((3y+19)*5)/(), so:

-((3y+19)*5)/(

We multiply all the terms by the denominator


-((3y+19)*5)



We calculate terms in parentheses: -((3y+19)*5), so:

(3y+19)*5

We multiply parentheses

15y+95

Back to the equation:

-(15y+95)



We get rid of parentheses

-15y-95

Back to the equation:

+(-15y-95)



We get rid of parentheses

(-9y)/()-15y-95=0

We multiply all the terms by the denominator


(-9y)-15y*()-95*()=0

We add all the numbers together, and all the variables

(-9y)-15y*()=0

We get rid of parentheses

-9y-15y*()=0

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