(1-b)5+2b=3

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Solution for (1-b)5+2b=3 equation: 



(1-b)5+2b=3

We move all terms to the left:

(1-b)5+2b-(3)=0

We add all the numbers together, and all the variables

(-1b+1)5+2b-3=0

We add all the numbers together, and all the variables

2b+(-1b+1)5-3=0

We multiply parentheses

2b-5b+5-3=0

We add all the numbers together, and all the variables

-3b+2=0

We move all terms containing b to the left, all other terms to the right

-3b=-2

b=-2/-3

b=2/3

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