(1-c)(1+c)=

Solution for (1-c)(1+c)= equation:

Simplifying
(1 + -1c)(1 + c) = 0

Multiply (1 + -1c) * (1 + c)
(1(1 + c) + -1c * (1 + c)) = 0
((1 * 1 + c * 1) + -1c * (1 + c)) = 0
((1 + 1c) + -1c * (1 + c)) = 0
(1 + 1c + (1 * -1c + c * -1c)) = 0
(1 + 1c + (-1c + -1c2)) = 0

Combine like terms: 1c + -1c = 0
(1 + 0 + -1c2) = 0
(1 + -1c2) = 0

Solving
1 + -1c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c2 = 0 + -1
-1c2 = 0 + -1

Combine like terms: 0 + -1 = -1
-1c2 = -1

Divide each side by '-1'.
c2 = 1

Simplifying
c2 = 1

Take the square root of each side:
c = {-1, 1}