(1-i)+(3i-2)=

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Solution for (1-i)+(3i-2)= equation:


Simplifying
(1 + -1i) + (3i + -2) = 0

Remove parenthesis around (1 + -1i)
1 + -1i + (3i + -2) = 0

Reorder the terms:
1 + -1i + (-2 + 3i) = 0

Remove parenthesis around (-2 + 3i)
1 + -1i + -2 + 3i = 0

Reorder the terms:
1 + -2 + -1i + 3i = 0

Combine like terms: 1 + -2 = -1
-1 + -1i + 3i = 0

Combine like terms: -1i + 3i = 2i
-1 + 2i = 0

Solving
-1 + 2i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 2i = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 2i = 0 + 1
2i = 0 + 1

Combine like terms: 0 + 1 = 1
2i = 1

Divide each side by '2'.
i = 0.5

Simplifying
i = 0.5

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