(1-j)(1+2j)(1-3j)=0

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Solution for (1-j)(1+2j)(1-3j)=0 equation: 


Simplifying
(1 + -1j)(1 + 2j)(1 + -3j) = 0

Multiply (1 + -1j) * (1 + 2j)
(1(1 + 2j) + -1j * (1 + 2j))(1 + -3j) = 0
((1 * 1 + 2j * 1) + -1j * (1 + 2j))(1 + -3j) = 0
((1 + 2j) + -1j * (1 + 2j))(1 + -3j) = 0
(1 + 2j + (1 * -1j + 2j * -1j))(1 + -3j) = 0
(1 + 2j + (-1j + -2j2))(1 + -3j) = 0

Combine like terms: 2j + -1j = 1j
(1 + 1j + -2j2)(1 + -3j) = 0

Multiply (1 + 1j + -2j2) * (1 + -3j)
(1(1 + -3j) + 1j * (1 + -3j) + -2j2 * (1 + -3j)) = 0
((1 * 1 + -3j * 1) + 1j * (1 + -3j) + -2j2 * (1 + -3j)) = 0
((1 + -3j) + 1j * (1 + -3j) + -2j2 * (1 + -3j)) = 0
(1 + -3j + (1 * 1j + -3j * 1j) + -2j2 * (1 + -3j)) = 0
(1 + -3j + (1j + -3j2) + -2j2 * (1 + -3j)) = 0
(1 + -3j + 1j + -3j2 + (1 * -2j2 + -3j * -2j2)) = 0
(1 + -3j + 1j + -3j2 + (-2j2 + 6j3)) = 0

Combine like terms: -3j + 1j = -2j
(1 + -2j + -3j2 + -2j2 + 6j3) = 0

Combine like terms: -3j2 + -2j2 = -5j2
(1 + -2j + -5j2 + 6j3) = 0

Solving
1 + -2j + -5j2 + 6j3 = 0

Solving for variable 'j'.

The solution to this equation could not be determined.

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