(1-k)/k+k+2

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Solution for (1-k)/k+k+2 equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

(1-k)/k+k+2 = 0

(1-k)/k+(k^2)/k+(2*k)/k = 0

k^2-k+2*k+1 = 0

k^2+k+1 = 0

k^2+k+1 = 0

k^2+k+1 = 0

DELTA = 1^2-(1*1*4)

DELTA = -3

DELTA < 0

1 = 0

1/k = 0

1/k = 0 // * k

1 = 0

k belongs to the empty set

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