(1-p)(1-p)=0.16

Solution for (1-p)(1-p)=0.16 equation:

(1-p)(1-p)=0.16

We move all terms to the left:

(1-p)(1-p)-(0.16)=0

We add all the numbers together, and all the variables

(-1p+1)(-1p+1)-(0.16)=0

We add all the numbers together, and all the variables

(-1p+1)(-1p+1)-0.16=0

We multiply parentheses ..

(+p^2-1p-1p+1)-0.16=0

We get rid of parentheses

p^2-1p-1p+1-0.16=0

We add all the numbers together, and all the variables

p^2-2p+0.84=0

a = 1; b = -2; c = +0.84;
Δ = b2-4ac
Δ = -22-4·1·0.84
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{0.64}}{2*1}=\frac{2-\sqrt{0.64}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{0.64}}{2*1}=\frac{2+\sqrt{0.64}}{2}
$