(1-r)(1-r)+4=0

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Solution for (1-r)(1-r)+4=0 equation:


Simplifying
(1 + -1r)(1 + -1r) + 4 = 0

Multiply (1 + -1r) * (1 + -1r)
(1(1 + -1r) + -1r * (1 + -1r)) + 4 = 0
((1 * 1 + -1r * 1) + -1r * (1 + -1r)) + 4 = 0
((1 + -1r) + -1r * (1 + -1r)) + 4 = 0
(1 + -1r + (1 * -1r + -1r * -1r)) + 4 = 0
(1 + -1r + (-1r + 1r2)) + 4 = 0

Combine like terms: -1r + -1r = -2r
(1 + -2r + 1r2) + 4 = 0

Reorder the terms:
1 + 4 + -2r + 1r2 = 0

Combine like terms: 1 + 4 = 5
5 + -2r + 1r2 = 0

Solving
5 + -2r + 1r2 = 0

Solving for variable 'r'.

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -2r + -5 + r2 = 0 + -5

Reorder the terms:
5 + -5 + -2r + r2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -2r + r2 = 0 + -5
-2r + r2 = 0 + -5

Combine like terms: 0 + -5 = -5
-2r + r2 = -5

The r term is -2r.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2r + 1 + r2 = -5 + 1

Reorder the terms:
1 + -2r + r2 = -5 + 1

Combine like terms: -5 + 1 = -4
1 + -2r + r2 = -4

Factor a perfect square on the left side:
(r + -1)(r + -1) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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