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(1-x)(0.5-x)=0
We add all the numbers together, and all the variables
(-1x+1)(-1x+0.5)=0
We multiply parentheses ..
(+x^2-0.5x-1x+0.5)=0
We get rid of parentheses
x^2-0.5x-1x+0.5=0
We add all the numbers together, and all the variables
x^2-1.5x+0.5=0
a = 1; b = -1.5; c = +0.5;
Δ = b2-4ac
Δ = -1.52-4·1·0.5
Δ = 0.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{0.25}}{2*1}=\frac{1.5-\sqrt{0.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{0.25}}{2*1}=\frac{1.5+\sqrt{0.25}}{2} $
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