(1-x)(x+2)=0

Solution for (1-x)(x+2)=0 equation:

Simplifying
(1 + -1x)(x + 2) = 0

Reorder the terms:
(1 + -1x)(2 + x) = 0

Multiply (1 + -1x) * (2 + x)
(1(2 + x) + -1x * (2 + x)) = 0
((2 * 1 + x * 1) + -1x * (2 + x)) = 0
((2 + 1x) + -1x * (2 + x)) = 0
(2 + 1x + (2 * -1x + x * -1x)) = 0
(2 + 1x + (-2x + -1x2)) = 0

Combine like terms: 1x + -2x = -1x
(2 + -1x + -1x2) = 0

Solving
2 + -1x + -1x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(1 + -1x)(2 + x) = 0

Subproblem 1
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Subproblem 2
Set the factor '(2 + x)' equal to zero and attempt to solve:

Simplifying
2 + x = 0

Solving
2 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + x = 0 + -2
x = 0 + -2

Combine like terms: 0 + -2 = -2
x = -2

Simplifying
x = -2
Solution
x = {1, -2}