(1-x)/2=(3x-7)/3

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Solution for (1-x)/2=(3x-7)/3 equation:



(1-x)/2=(3x-7)/3
We move all terms to the left:
(1-x)/2-((3x-7)/3)=0
We add all the numbers together, and all the variables
(-1x+1)/2-((3x-7)/3)=0
We calculate fractions
(-x)/()+(-((3x-7)*2)/()=0
We calculate terms in parentheses: +(-((3x-7)*2)/(), so:
-((3x-7)*2)/(
We multiply all the terms by the denominator
-((3x-7)*2)
We calculate terms in parentheses: -((3x-7)*2), so:
(3x-7)*2
We multiply parentheses
6x-14
Back to the equation:
-(6x-14)
We get rid of parentheses
-6x+14
Back to the equation:
+(-6x+14)
We add all the numbers together, and all the variables
(-1x)/()+(-6x+14)=0
We get rid of parentheses
(-1x)/()-6x+14=0
We multiply all the terms by the denominator
(-1x)-6x*()+14*()=0
We add all the numbers together, and all the variables
(-1x)-6x*()=0
We get rid of parentheses
-1x-6x*()=0

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