(1-x)/2=(3x-7)/3

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Solution for (1-x)/2=(3x-7)/3 equation: 



(1-x)/2=(3x-7)/3

We move all terms to the left:

(1-x)/2-((3x-7)/3)=0

We add all the numbers together, and all the variables

(-1x+1)/2-((3x-7)/3)=0

We calculate fractions


(-x)/()+(-((3x-7)*2)/()=0



We calculate terms in parentheses: +(-((3x-7)*2)/(), so:

-((3x-7)*2)/(

We multiply all the terms by the denominator


-((3x-7)*2)



We calculate terms in parentheses: -((3x-7)*2), so:

(3x-7)*2

We multiply parentheses

6x-14

Back to the equation:

-(6x-14)



We get rid of parentheses

-6x+14

Back to the equation:

+(-6x+14)



We add all the numbers together, and all the variables

(-1x)/()+(-6x+14)=0

We get rid of parentheses

(-1x)/()-6x+14=0

We multiply all the terms by the denominator


(-1x)-6x*()+14*()=0

We add all the numbers together, and all the variables

(-1x)-6x*()=0

We get rid of parentheses

-1x-6x*()=0

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