(1-y)/5=(y+1)/2-1

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Solution for (1-y)/5=(y+1)/2-1 equation: 



(1-y)/5=(y+1)/2-1

We move all terms to the left:

(1-y)/5-((y+1)/2-1)=0

We add all the numbers together, and all the variables

(-1y+1)/5-((y+1)/2-1)=0

We calculate fractions


(-2y+2)/()+(-((y+1)*5)/()=0



We calculate terms in parentheses: +(-((y+1)*5)/(), so:

-((y+1)*5)/(

We multiply all the terms by the denominator


-((y+1)*5)



We calculate terms in parentheses: -((y+1)*5), so:

(y+1)*5

We multiply parentheses

5y+5

Back to the equation:

-(5y+5)



We get rid of parentheses

-5y-5

Back to the equation:

+(-5y-5)



We get rid of parentheses

(-2y+2)/()-5y-5=0

We multiply all the terms by the denominator


(-2y+2)-5y*()-5*()=0

We add all the numbers together, and all the variables

(-2y+2)-5y*()=0

We get rid of parentheses

-2y-5y*()+2=0

We move all terms containing y to the left, all other terms to the right

-2y-5y*()=-2

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