(1.06(x+550))/2=212+1.06(2x)

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Solution for (1.06(x+550))/2=212+1.06(2x) equation: 



(1.06(x+550))/2=212+1.06(2x)

We move all terms to the left:

(1.06(x+550))/2-(212+1.06(2x))=0

We add all the numbers together, and all the variables

(1.06(x+550))/2-(1.062x+212)=0

We get rid of parentheses

(1.06(x+550))/2-1.062x-212=0

We multiply all the terms by the denominator


(1.06(x+550))-(1.062x)*2-212*2=0



We calculate terms in parentheses: +(1.06(x+550)), so:

1.06(x+550)

We multiply parentheses

1.06x+583

Back to the equation:

+(1.06x+583)



We add all the numbers together, and all the variables

(1.06x+583)-(+1.062x)*2-212*2=0

We add all the numbers together, and all the variables

(1.06x+583)-(+1.062x)*2-424=0

We multiply parentheses

(1.06x+583)-2x-424=0

We get rid of parentheses

1.06x-2x+583-424=0

We add all the numbers together, and all the variables

-0.94x+159=0

We move all terms containing x to the left, all other terms to the right

-0.94x=-159

x=-159/-0.94

x=169+0.14/0.94

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