(1/(4+y))+(1/y)=(2/3)

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Solution for (1/(4+y))+(1/y)=(2/3) equation:


D( y )

y = 0

y+4 = 0

y = 0

y = 0

y+4 = 0

y+4 = 0

y+4 = 0 // - 4

y = -4

y in (-oo:-4) U (-4:0) U (0:+oo)

1/(y+4)+1/y = 2/3 // - 2/3

1/(y+4)+1/y-(2/3) = 0

1/(y+4)+1/y-2/3 = 0

(1*3*y)/(3*y*(y+4))+(1*3*(y+4))/(3*y*(y+4))+(-2*y*(y+4))/(3*y*(y+4)) = 0

1*3*(y+4)-2*y*(y+4)+1*3*y = 0

6*y-2*y^2-8*y+12 = 0

12-2*y^2-2*y = 0

12-2*y^2-2*y = 0

2*(6-y^2-y) = 0

6-y^2-y = 0

DELTA = (-1)^2-(-1*4*6)

DELTA = 25

DELTA > 0

y = (25^(1/2)+1)/(-1*2) or y = (1-25^(1/2))/(-1*2)

y = -3 or y = 2

2*(y+3)*(y-2) = 0

(2*(y+3)*(y-2))/(3*y*(y+4)) = 0

(2*(y+3)*(y-2))/(3*y*(y+4)) = 0 // * 3*y*(y+4)

2*(y+3)*(y-2) = 0

( y+3 )

y+3 = 0 // - 3

y = -3

( y-2 )

y-2 = 0 // + 2

y = 2

y in { -3, 2 }

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