(1/(4x+5))+(1(2x-2))=1

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Solution for (1/(4x+5))+(1(2x-2))=1 equation:


D( x )

4*x+5 = 0

4*x+5 = 0

4*x+5 = 0

4*x+5 = 0 // - 5

4*x = -5 // : 4

x = -5/4

x in (-oo:-5/4) U (-5/4:+oo)

1/(4*x+5)+1*(2*x-2) = 1 // - 1

1/(4*x+5)+1*(2*x-2)-1 = 0

1/(4*x+5)+2*x-2-1 = 0

1/(4*x+5)+(2*x*(4*x+5))/(4*x+5)+(-2*(4*x+5))/(4*x+5)+(-1*(4*x+5))/(4*x+5) = 0

2*x*(4*x+5)-2*(4*x+5)-1*(4*x+5)+1 = 0

8*x^2+10*x-8*x-4*x-10-5+1 = 0

8*x^2+2*x-4*x-9-5 = 0

8*x^2-2*x-14 = 0

8*x^2-2*x-14 = 0

2*(4*x^2-x-7) = 0

4*x^2-x-7 = 0

DELTA = (-1)^2-(-7*4*4)

DELTA = 113

DELTA > 0

x = (113^(1/2)+1)/(2*4) or x = (1-113^(1/2))/(2*4)

x = (113^(1/2)+1)/8 or x = (1-113^(1/2))/8

2*(x-((1-113^(1/2))/8))*(x-((113^(1/2)+1)/8)) = 0

(2*(x-((1-113^(1/2))/8))*(x-((113^(1/2)+1)/8)))/(4*x+5) = 0

(2*(x-((1-113^(1/2))/8))*(x-((113^(1/2)+1)/8)))/(4*x+5) = 0 // * 4*x+5

2*(x-((1-113^(1/2))/8))*(x-((113^(1/2)+1)/8)) = 0

( x-((1-113^(1/2))/8) )

x-((1-113^(1/2))/8) = 0 // + (1-113^(1/2))/8

x = (1-113^(1/2))/8

( x-((113^(1/2)+1)/8) )

x-((113^(1/2)+1)/8) = 0 // + (113^(1/2)+1)/8

x = (113^(1/2)+1)/8

x in { (1-113^(1/2))/8, (113^(1/2)+1)/8 }

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