(1/(w-1))-(1/(2w-2))=(1/(2w-2))

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Solution for (1/(w-1))-(1/(2w-2))=(1/(2w-2)) equation: 


D( w )

2*w-2 = 0

w-1 = 0

2*w-2 = 0

2*w-2 = 0

2*w-2 = 0 // + 2

2*w = 2 // : 2

w = 2/2

w = 1

w-1 = 0

w-1 = 0

w-1 = 0 // + 1

w = 1

w in (-oo:1) U (1:+oo)

1/(w-1)-(1/(2*w-2)) = 1/(2*w-2) // - 1/(2*w-2)

1/(w-1)-(1/(2*w-2))-(1/(2*w-2)) = 0

1/(w-1)-(2*w-2)^-1-(2*w-2)^-1 = 0

1/(w-1)-1/(2*w-2)-1/(2*w-2) = 0

(1*(2*w-2))/((w-1)*(2*w-2))+(-1*(w-1))/((w-1)*(2*w-2))+(-1*(w-1))/((w-1)*(2*w-2)) = 0

1*(2*w-2)-1*(w-1)-1*(w-1) = 0

w-w-1+1 = 0

0 = 0

0/((w-1)*(2*w-2)) = 0

0/((w-1)*(2*w-2)) = 0 // * (w-1)*(2*w-2)

0 = 0

w belongs to the empty set

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