(1/(x+1))=(1)-(2/(x+3))

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Solution for (1/(x+1))=(1)-(2/(x+3)) equation: 


D( x )

x+1 = 0

x+3 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:-1) U (-1:+oo)

1/(x+1) = 1-(2/(x+3)) // - 1-(2/(x+3))

1/(x+1)+2/(x+3)-1 = 0

(1*(x+3))/((x+1)*(x+3))+(2*(x+1))/((x+1)*(x+3))+(-1*(x+1)*(x+3))/((x+1)*(x+3)) = 0

1*(x+3)+2*(x+1)-1*(x+1)*(x+3) = 0

3*x-x^2-4*x-3+5 = 0

2-x^2-x = 0

2-x^2-x = 0

2-x^2-x = 0

DELTA = (-1)^2-(-1*2*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(-1*2) or x = (1-9^(1/2))/(-1*2)

x = -2 or x = 1

(x+2)*(x-1) = 0

((x+2)*(x-1))/((x+1)*(x+3)) = 0

((x+2)*(x-1))/((x+1)*(x+3)) = 0 // * (x+1)*(x+3)

(x+2)*(x-1) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -2, 1 }

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