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(1/(x+2))+(1/(x-2))=18/(5x)
We move all terms to the left:
(1/(x+2))+(1/(x-2))-(18/(5x))=0
Domain of the equation: (x+2))!=0
x∈R
Domain of the equation: (x-2))!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(1/(x+2))+(1/(x-2))-(+18/5x)=0
We get rid of parentheses
(1/(x+2))+(1/(x-2))-18/5x=0
We calculate fractions
((1*(x-2))*5x)/((x+2))*(x-2))*5x)+((1*(x+2))*5x)/((x+2))*(x-2))*5x)+(-18*(x+2))*x/((x+2))*(x-2))*5x)=0
We can not solve this equation
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