(1/(x+2))=0

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Solution for (1/(x+2))=0 equation:


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

1/(x+2) = 0

x belongs to the empty set

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