(1/(x+6))+(1/(x+1))+(1/2x)=1/x

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Solution for (1/(x+6))+(1/(x+1))+(1/2x)=1/x equation: 



(1/(x+6))+(1/(x+1))+(1/2x)=1/x

We move all terms to the left:

(1/(x+6))+(1/(x+1))+(1/2x)-(1/x)=0



Domain of the equation: (x+6))!=0

x∈R





Domain of the equation: (x+1))!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(1/(x+6))+(1/(x+1))+(+1/2x)-(+1/x)=0

We get rid of parentheses

(1/(x+6))+(1/(x+1))+1/2x-1/x=0

We calculate fractions


((1*(x+1))*2x*x)/((x+6))*(x+1))*2x*x)+((1*(x+6))*2x*x)/((x+6))*(x+1))*2x*x)+(1*(x+6))*(x+1))*x)/((x+6))*(x+1))*2x*x)+(-1*(x+6))*(x+1))*2x)/((x+6))*(x+1))*2x*x)=0

We can not solve this equation

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