(1/0.19)=(12/n)

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Solution for (1/0.19)=(12/n) equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

1/0.19 = 12/n // - 12/n

1/0.19-(12/n) = 0

1/0.19-12*n^-1 = 0

-12*n^-1 = -5.26315789 // : -12

n^-1 = 0.43859649

-1 < 0

1/(n^1) = 0.43859649 // * n^1

1 = 0.43859649*n^1 // : 0.43859649

2.28000001 = n^1

n = 2.28000001

n = 2.28000001

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