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(1/12)x=13/6
We move all terms to the left:
(1/12)x-(13/6)=0
Domain of the equation: 12)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/12)x-(+13/6)=0
We multiply parentheses
x^2-(+13/6)=0
We get rid of parentheses
x^2-13/6=0
We multiply all the terms by the denominator
x^2*6-13=0
Wy multiply elements
6x^2-13=0
a = 6; b = 0; c = -13;
Δ = b2-4ac
Δ = 02-4·6·(-13)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{78}}{2*6}=\frac{0-2\sqrt{78}}{12} =-\frac{2\sqrt{78}}{12} =-\frac{\sqrt{78}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{78}}{2*6}=\frac{0+2\sqrt{78}}{12} =\frac{2\sqrt{78}}{12} =\frac{\sqrt{78}}{6} $
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