(1/1x-1)+4=(17/1x-1)

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Solution for (1/1x-1)+4=(17/1x-1) equation: 



(1/1x-1)+4=(17/1x-1)

We move all terms to the left:

(1/1x-1)+4-((17/1x-1))=0



Domain of the equation: 1x-1)!=0

x∈R





Domain of the equation: 1x-1))!=0

x∈R



We get rid of parentheses

1/1x-((17/1x-1))-1+4=0

We calculate fractions


x/x^2+(-((17*1x)/x^2-1+4=0

We add all the numbers together, and all the variables

x/x^2+(-((+17*1x)/x^2-1+4=0

We calculate fractions

We do not support expression: x^4

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