(1/2)((n+4)(n-7))=6

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Solution for (1/2)((n+4)(n-7))=6 equation: 



(1/2)((n+4)(n-7))=6

We move all terms to the left:

(1/2)((n+4)(n-7))-(6)=0



Domain of the equation: 2)((n+4)(n-7))!=0

n∈R



We add all the numbers together, and all the variables

(+1/2)((n+4)(n-7))-6=0

We multiply parentheses ..

(+1/2)((+n^2-7n+4n-28))-6=0

We multiply all the terms by the denominator


(+1-6*2)((+n^2-7n+4n-28))=0



We calculate terms in parentheses: +(+1-6*2)((+n^2-7n+4n-28)), so:

+1-6*2)((+n^2-7n+4n-28)

determiningTheFunctionDomain
-6*2)((+n^2-7n+4n-28)+1

Wy multiply elements

-12n+1

Back to the equation:

+(-12n+1)



We get rid of parentheses

-12n+1=0

We move all terms containing n to the left, all other terms to the right

-12n=-1

n=-1/-12

n=1/12

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