(1/2)(1+2t)=1/2(1)+1/2(2t)

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Solution for (1/2)(1+2t)=1/2(1)+1/2(2t) equation: 


t in (-oo:+oo)

(1/2)*(2*t+1) = 2*(1/2)*t+1*(1/2) // - 2*(1/2)*t+1*(1/2)

(1/2)*(2*t+1)-(2*(1/2)*t)-(1*(1/2)) = 0

(1/2)*(2*t+1)-t-1/2 = 0

1/2*(2*t+1)-t-1/2 = 0

(1/2*2*(2*t+1))/2+(2*(-t))/2-1/2 = 0

1/2*2*(2*t+1)+2*(-t)-1 = 0

1-1 = 0

0 = 0

0/2 = 0

0/2 = 0 // * 2

0 = 0

t belongs to the empty set

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