(1/2)(10t)=50;000

Solution for (1/2)(10t)=50;000 equation:

(1/2)(10t)=50000

We move all terms to the left:

(1/2)(10t)-(50000)=0


Domain of the equation: 2)10t!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

(+1/2)10t-50000=0

We multiply parentheses

10t^2-50000=0

a = 10; b = 0; c = -50000;
Δ = b2-4ac
Δ = 02-4·10·(-50000)
Δ = 2000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2000000}=\sqrt{1000000*2}=\sqrt{1000000}*\sqrt{2}=1000\sqrt{2}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1000\sqrt{2}}{2*10}=\frac{0-1000\sqrt{2}}{20}
=-\frac{1000\sqrt{2}}{20}
=-50\sqrt{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1000\sqrt{2}}{2*10}=\frac{0+1000\sqrt{2}}{20}
=\frac{1000\sqrt{2}}{20}
=50\sqrt{2}
$