(1/2)(10x)=50000

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Solution for (1/2)(10x)=50000 equation:



(1/2)(10x)=50000
We move all terms to the left:
(1/2)(10x)-(50000)=0
Domain of the equation: 2)10x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+1/2)10x-50000=0
We multiply parentheses
10x^2-50000=0
a = 10; b = 0; c = -50000;
Δ = b2-4ac
Δ = 02-4·10·(-50000)
Δ = 2000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2000000}=\sqrt{1000000*2}=\sqrt{1000000}*\sqrt{2}=1000\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1000\sqrt{2}}{2*10}=\frac{0-1000\sqrt{2}}{20} =-\frac{1000\sqrt{2}}{20} =-50\sqrt{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1000\sqrt{2}}{2*10}=\frac{0+1000\sqrt{2}}{20} =\frac{1000\sqrt{2}}{20} =50\sqrt{2} $

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