(1/2)(10x-18)-13x=-2x+7-6x

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Solution for (1/2)(10x-18)-13x=-2x+7-6x equation:



(1/2)(10x-18)-13x=-2x+7-6x
We move all terms to the left:
(1/2)(10x-18)-13x-(-2x+7-6x)=0
Domain of the equation: 2)(10x-18)!=0
x∈R
We add all the numbers together, and all the variables
(+1/2)(10x-18)-13x-(-8x+7)=0
We add all the numbers together, and all the variables
-13x+(+1/2)(10x-18)-(-8x+7)=0
We get rid of parentheses
-13x+(+1/2)(10x-18)+8x-7=0
We multiply parentheses ..
(+10x^2+1/2*-18)-13x+8x-7=0
We multiply all the terms by the denominator
(+10x^2+1-13x*2*-18)+8x*2*-18)-7*2*-18)=0
We add all the numbers together, and all the variables
(+10x^2+1-13x*2*-18)+8x*2*=0
Wy multiply elements
(+10x^2+1-13x*2*-18)+16x^2=0
We get rid of parentheses
10x^2+16x^2-13x*2*+1-18=0
We add all the numbers together, and all the variables
26x^2-13x*2*-17=0
Wy multiply elements
26x^2-26x^2-17=0
We add all the numbers together, and all the variables
-17!=0
There is no solution for this equation

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