(1/2)(10x-4)=38

Solution for (1/2)(10x-4)=38 equation:

(1/2)(10x-4)=38

We move all terms to the left:

(1/2)(10x-4)-(38)=0


Domain of the equation: 2)(10x-4)!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)(10x-4)-38=0

We multiply parentheses ..

(+10x^2+1/2*-4)-38=0

We multiply all the terms by the denominator


(+10x^2+1-38*2*-4)=0

We get rid of parentheses

10x^2+1-4-38*2*=0

We add all the numbers together, and all the variables

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$