(1/2)(2w-4)=-10

Solution for (1/2)(2w-4)=-10 equation:

(1/2)(2w-4)=-10

We move all terms to the left:

(1/2)(2w-4)-(-10)=0


Domain of the equation: 2)(2w-4)!=0

w∈R


We add all the numbers together, and all the variables

(+1/2)(2w-4)-(-10)=0

We add all the numbers together, and all the variables

(+1/2)(2w-4)+10=0

We multiply parentheses ..

(+2w^2+1/2*-4)+10=0

We multiply all the terms by the denominator


(+2w^2+1+10*2*-4)=0

We get rid of parentheses

2w^2+1-4+10*2*=0

We add all the numbers together, and all the variables

2w^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{4}=0$