(1/2)(2x-4)-(1/3x)=(4/3x)-4

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Solution for (1/2)(2x-4)-(1/3x)=(4/3x)-4 equation: 



(1/2)(2x-4)-(1/3x)=(4/3x)-4

We move all terms to the left:

(1/2)(2x-4)-(1/3x)-((4/3x)-4)=0



Domain of the equation: 2)(2x-4)!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3x)-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(2x-4)-(+1/3x)-((+4/3x)-4)=0

We get rid of parentheses

(+1/2)(2x-4)-1/3x-((+4/3x)-4)=0

We multiply parentheses ..

(+2x^2+1/2*-4)-1/3x-((+4/3x)-4)=0

We calculate fractions


29x^2/(-4)*3x*3x)-4)+2*)+(-4)*3x)-4)-1*2*)/(-4)*3x*3x)-4)+2*)+(-((-32)*3x)/(-4)*3x*3x)-4)+2*)=0

We can not solve this equation

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