(1/2)(2x-4)=8

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Solution for (1/2)(2x-4)=8 equation: 



(1/2)(2x-4)=8

We move all terms to the left:

(1/2)(2x-4)-(8)=0



Domain of the equation: 2)(2x-4)!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(2x-4)-8=0

We multiply parentheses ..

(+2x^2+1/2*-4)-8=0

We multiply all the terms by the denominator


(+2x^2+1-8*2*-4)=0

We get rid of parentheses

2x^2+1-4-8*2*=0

We add all the numbers together, and all the variables

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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