(1/2)(3x-6)-15=12*

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Solution for (1/2)(3x-6)-15=12* equation: 



(1/2)(3x-6)-15=12*

We move all terms to the left:

(1/2)(3x-6)-15-(12*)=0



Domain of the equation: 2)(3x-6)!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(3x-6)-15-0=0

We add all the numbers together, and all the variables

(+1/2)(3x-6)-15=0

We multiply parentheses ..

(+3x^2+1/2*-6)-15=0

We multiply all the terms by the denominator


(+3x^2+1-15*2*-6)=0

We get rid of parentheses

3x^2+1-6-15*2*=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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