(1/2)(4x-2)=3

Solution for (1/2)(4x-2)=3 equation:

(1/2)(4x-2)=3

We move all terms to the left:

(1/2)(4x-2)-(3)=0


Domain of the equation: 2)(4x-2)!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)(4x-2)-3=0

We multiply parentheses ..

(+4x^2+1/2*-2)-3=0

We multiply all the terms by the denominator


(+4x^2+1-3*2*-2)=0

We get rid of parentheses

4x^2+1-2-3*2*=0

We add all the numbers together, and all the variables

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$