(1/2)(4x-8)=(1/5)(20x-10)

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Solution for (1/2)(4x-8)=(1/5)(20x-10) equation:



(1/2)(4x-8)=(1/5)(20x-10)
We move all terms to the left:
(1/2)(4x-8)-((1/5)(20x-10))=0
Domain of the equation: 2)(4x-8)!=0
x∈R
Domain of the equation: 5)(20x-10))!=0
x∈R
We add all the numbers together, and all the variables
(+1/2)(4x-8)-((+1/5)(20x-10))=0
We multiply parentheses ..
(+4x^2+1/2*-8)-((+1/5)(20x-10))=0
We calculate fractions
((+4x^2+1*5)(20x-10)))/(-8)*5)(20x-10))+2*)+()/(-8)*5)(20x-10))+2*)=0
We calculate fractions
(((+4x^2+1*5)(20x-10)))*(-8)*5)(20x-10))+2*))/((*(-8)*5)20x)+(-8)*5)(20x-10))+2*)+()*()/((*(-8)*5)20x)=0
We can not solve this equation

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