(1/2)(4x-8)=x-4+x

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Solution for (1/2)(4x-8)=x-4+x equation: 


x in (-oo:+oo)

(1/2)*(4*x-8) = x+x-4 // - x+x-4

(1/2)*(4*x-8)-x-x+4 = 0

1/2*(4*x-8)-x-x+4 = 0

1/2*(4*x-8)-x-x+4 = 0

x-x-4+4 = 0

4-4 = 0

0 = 0

0 = 0

x belongs to the empty set

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