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(1/2)(5x+2)=(1/3)(6x-7)
We move all terms to the left:
(1/2)(5x+2)-((1/3)(6x-7))=0
Domain of the equation: 2)(5x+2)!=0
x∈R
Domain of the equation: 3)(6x-7))!=0We add all the numbers together, and all the variables
x∈R
(+1/2)(5x+2)-((+1/3)(6x-7))=0
We multiply parentheses ..
(+5x^2+1/2*2)-((+1/3)(6x-7))=0
We calculate fractions
((+5x^2+1*3)(6x-7)))/12x^2+()/12x^2=0
We can not solve this equation
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