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(1/2)(5x-2)+1=(-7/2)x-3
We move all terms to the left:
(1/2)(5x-2)+1-((-7/2)x-3)=0
Domain of the equation: 2)(5x-2)!=0
x∈R
Domain of the equation: 2)x-3)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/2)(5x-2)-((-7/2)x-3)+1=0
We multiply parentheses ..
(+5x^2+1/2*-2)-((-7/2)x-3)+1=0
We calculate fractions
We do not support expression: x^3
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