(1/2)(5x-8)+2=12

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Solution for (1/2)(5x-8)+2=12 equation: 



(1/2)(5x-8)+2=12

We move all terms to the left:

(1/2)(5x-8)+2-(12)=0



Domain of the equation: 2)(5x-8)!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(5x-8)+2-12=0

We add all the numbers together, and all the variables

(+1/2)(5x-8)-10=0

We multiply parentheses ..

(+5x^2+1/2*-8)-10=0

We multiply all the terms by the denominator


(+5x^2+1-10*2*-8)=0

We get rid of parentheses

5x^2+1-8-10*2*=0

We add all the numbers together, and all the variables

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$

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