(1/2)(6)-(4/5)y=19

Solution for (1/2)(6)-(4/5)y=19 equation:

(1/2)(6)-(4/5)y=19

We move all terms to the left:

(1/2)(6)-(4/5)y-(19)=0


Domain of the equation: 5)y!=0

y!=0/1

y!=0

y∈R


determiningTheFunctionDomain
-(4/5)y-19+(1/2)6=0

We add all the numbers together, and all the variables

-(+4/5)y-19+(+1/2)6=0

We multiply parentheses

-4y^2-19+1/2*6=0

We multiply all the terms by the denominator


-4y^2*2*6+1-19*2*6=0

We add all the numbers together, and all the variables

-4y^2*2*6-227=0

Wy multiply elements

-48y^2*6-227=0

Wy multiply elements

-288y^2-227=0

a = -288; b = 0; c = -227;
Δ = b2-4ac
Δ = 02-4·(-288)·(-227)
Δ = -261504
Delta is less than zero, so there is no solution for the equation