(1/2)(6x+3)-8-(3x-9)=(13/2)

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Solution for (1/2)(6x+3)-8-(3x-9)=(13/2) equation: 



(1/2)(6x+3)-8-(3x-9)=(13/2)

We move all terms to the left:

(1/2)(6x+3)-8-(3x-9)-((13/2))=0



Domain of the equation: 2)(6x+3)!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(6x+3)-(3x-9)-8-((+13/2))=0

We get rid of parentheses

(+1/2)(6x+3)-3x+9-8-((+13/2))=0

We multiply parentheses ..

(+6x^2+1/2*3)-3x+9-8-((+13/2))=0

We calculate fractions


6x^2/()-3x+9-8+()/()=0

We add all the numbers together, and all the variables

6x^2/()-3x+2=0

We multiply all the terms by the denominator


6x^2-3x*()+2*()=0

We add all the numbers together, and all the variables

6x^2-3x*()=0

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