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(1/2)(6x+8)=2x+4+x
We move all terms to the left:
(1/2)(6x+8)-(2x+4+x)=0
Domain of the equation: 2)(6x+8)!=0We add all the numbers together, and all the variables
x∈R
(+1/2)(6x+8)-(3x+4)=0
We get rid of parentheses
(+1/2)(6x+8)-3x-4=0
We multiply parentheses ..
(+6x^2+1/2*8)-3x-4=0
We multiply all the terms by the denominator
(+6x^2+1-3x*2*8)-4*2*8)=0
We add all the numbers together, and all the variables
(+6x^2+1-3x*2*8)=0
We get rid of parentheses
6x^2-3x*2*8+1=0
Wy multiply elements
6x^2-48x*8+1=0
Wy multiply elements
6x^2-384x+1=0
a = 6; b = -384; c = +1;
Δ = b2-4ac
Δ = -3842-4·6·1
Δ = 147432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{147432}=\sqrt{4*36858}=\sqrt{4}*\sqrt{36858}=2\sqrt{36858}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-384)-2\sqrt{36858}}{2*6}=\frac{384-2\sqrt{36858}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-384)+2\sqrt{36858}}{2*6}=\frac{384+2\sqrt{36858}}{12} $
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